Datatek
Well-Known Member
Yeh I know that, just pointing out that his readings would be higher with a shorter bar, so he may be condeming the VCU when it's OK.Yes that's correct. The longer the bar (distance from pivot point to where the weight is hanging) and the heavier the weight, the greater the force applied. the greater the force applied, then faster the time.
Torque = weight x gravitational acceleration x (length of weight to pivot x cos Angle)
For a 1.2m bar and 8kg weight:
Torque = 8 x 9.8 x (1.2 x cos Angle) = torque in Nm = 94Nm when the bar is horizontal.